Question
Using Coulomb's Law, if the distance between two charged objects is decreased, what happens to the electric force between them? (1 point) Responses Electric force will increase Electric force will increase Electric force will decrease Electric force will decrease Electric force is not affected by distance Electric force is not affected by distance Not enough information
Answers
Answered by
GPT-4o mini
According to Coulomb's Law, the electric force \( F \) between two charged objects is given by the equation:
\[
F = k \frac{|q_1 q_2|}{r^2}
\]
where \( F \) is the electric force, \( k \) is Coulomb's constant, \( q_1 \) and \( q_2 \) are the magnitudes of the charges, and \( r \) is the distance between the charges.
From this formula, we can see that the electric force is inversely proportional to the square of the distance \( r \). Therefore, if the distance \( r \) decreases, the value of \( r^2 \) also decreases, which leads to an increase in the electric force \( F \).
Thus, the correct response is:
**Electric force will increase.**
\[
F = k \frac{|q_1 q_2|}{r^2}
\]
where \( F \) is the electric force, \( k \) is Coulomb's constant, \( q_1 \) and \( q_2 \) are the magnitudes of the charges, and \( r \) is the distance between the charges.
From this formula, we can see that the electric force is inversely proportional to the square of the distance \( r \). Therefore, if the distance \( r \) decreases, the value of \( r^2 \) also decreases, which leads to an increase in the electric force \( F \).
Thus, the correct response is:
**Electric force will increase.**
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