In which situation did the car achieve the greatest efficiency? (Assume the cars all have the same mass.)(1 point)

Responses

a car that traveled 80 kilometers on 5.0 liters of gas
a car that traveled 80 kilometers on 5.0 liters of gas

a car that traveled 90 kilometers on 6.0 liters of gas
a car that traveled 90 kilometers on 6.0 liters of gas

a car that traveled 50 kilometers on 4.0 liters of gas
a car that traveled 50 kilometers on 4.0 liters of gas

a car that traveled 70 kilometers on 5.0 liters of gas

1 answer

To determine which car achieved the greatest efficiency in terms of kilometers per liter of gas, we can calculate the fuel efficiency for each situation by dividing the distance traveled (in kilometers) by the amount of gas used (in liters).

  1. Car A: 80 kilometers on 5.0 liters
    Efficiency = 80 km / 5.0 L = 16 km/L

  2. Car B: 90 kilometers on 6.0 liters
    Efficiency = 90 km / 6.0 L = 15 km/L

  3. Car C: 50 kilometers on 4.0 liters
    Efficiency = 50 km / 4.0 L = 12.5 km/L

  4. Car D: 70 kilometers on 5.0 liters
    Efficiency = 70 km / 5.0 L = 14 km/L

Now, comparing the efficiencies:

  • Car A: 16 km/L
  • Car B: 15 km/L
  • Car C: 12.5 km/L
  • Car D: 14 km/L

The car that achieved the greatest efficiency is Car A, which traveled 80 kilometers on 5.0 liters of gas, giving it an efficiency of 16 km/L.