Question

the woodson and baker went to the burger shack for dinner. The woodsons bought 3 burger meals and 4 hot dog meals for 48 dollars the bakers bought 6 burger meals and 2 hot dog meals for 60 dollars. How much does each meal cost? show your work(SHORT ANSWER)

Answer 1

Let \( b \) be the cost of a burger meal and \( h \) be the cost of a hot dog meal.

From the information provided, we can set up the following equations:

1. \( 3b + 4h = 48 \) (Woodson's order)
2. \( 6b + 2h = 60 \) (Baker's order)

Now, we can simplify the second equation:

Divide the entire equation \( 6b + 2h = 60 \) by 2:

\[
3b + h = 30
\]

Now we have the two equations:
1. \( 3b + 4h = 48 \)
2. \( 3b + h = 30 \)

Next, we can subtract the second equation from the first:

\[
(3b + 4h) - (3b + h) = 48 - 30
\]

This simplifies to:

\[
3h = 18
\]

Now, divide by 3:

\[
h = 6
\]

Now, substitute \( h = 6 \) back into the second equation:

\[
3b + 6 = 30
\]

Subtract 6 from both sides:

\[
3b = 24
\]

Now divide by 3:

\[
b = 8
\]

Thus, the cost of each meal is:
- Burger meal: **$8**
- Hot dog meal: **$6**