Let \( b \) be the cost of a burger meal and \( h \) be the cost of a hot dog meal.
From the information provided, we can set up the following equations:
- \( 3b + 4h = 48 \) (Woodson's order)
- \( 6b + 2h = 60 \) (Baker's order)
Now, we can simplify the second equation:
Divide the entire equation \( 6b + 2h = 60 \) by 2:
\[ 3b + h = 30 \]
Now we have the two equations:
- \( 3b + 4h = 48 \)
- \( 3b + h = 30 \)
Next, we can subtract the second equation from the first:
\[ (3b + 4h) - (3b + h) = 48 - 30 \]
This simplifies to:
\[ 3h = 18 \]
Now, divide by 3:
\[ h = 6 \]
Now, substitute \( h = 6 \) back into the second equation:
\[ 3b + 6 = 30 \]
Subtract 6 from both sides:
\[ 3b = 24 \]
Now divide by 3:
\[ b = 8 \]
Thus, the cost of each meal is:
- Burger meal: $8
- Hot dog meal: $6