Asked by hsdfghsdxvzc
Use the table to answer the question.
x-Values y-Values
0 5
1 15
2 45
3 135
4 405
Select the function that best models the data and determine the value of the function at x=−1
.
(1 point)
Responses
f(x)=5⋅3x
; f(−1)=53
f of x is equal to 5 times 3 to the x th power; f of negative 1 is equal to 5 thirds
f(x)=41.43x2−73.71x+19.86
; f(−1)=135
f of x is equal to 41 point 4 3 x squared minus 73 point 7 1 x plus 19 point 8 6; f of negative 1 is equal to 135
f(x)=92x−63
; f(−1)=−155
f of x is equal to 92 x minus 63; f of negative 1 is equal to negative 155
f(x)=2.23⋅(1.40)x
; f(−1)=1.59
x-Values y-Values
0 5
1 15
2 45
3 135
4 405
Select the function that best models the data and determine the value of the function at x=−1
.
(1 point)
Responses
f(x)=5⋅3x
; f(−1)=53
f of x is equal to 5 times 3 to the x th power; f of negative 1 is equal to 5 thirds
f(x)=41.43x2−73.71x+19.86
; f(−1)=135
f of x is equal to 41 point 4 3 x squared minus 73 point 7 1 x plus 19 point 8 6; f of negative 1 is equal to 135
f(x)=92x−63
; f(−1)=−155
f of x is equal to 92 x minus 63; f of negative 1 is equal to negative 155
f(x)=2.23⋅(1.40)x
; f(−1)=1.59
Answers
Answered by
GPT-4o mini
To determine the function that best models the data and calculate the value of the function at \( x = -1 \), we can first examine the provided data:
| x-Values | y-Values |
|----------|----------|
| 0 | 5 |
| 1 | 15 |
| 2 | 45 |
| 3 | 135 |
| 4 | 405 |
From observing the values, we can see that:
- \( y(0) = 5 \)
- \( y(1) = 15 = 5 \cdot 3 \)
- \( y(2) = 45 = 5 \cdot 3^2 \)
- \( y(3) = 135 = 5 \cdot 3^3 \)
- \( y(4) = 405 = 5 \cdot 3^4 \)
This suggests that the function could be modeled by the equation \( f(x) = 5 \cdot 3^x \).
Now, let's confirm if this function fits and calculate \( f(-1) \):
\[ f(-1) = 5 \cdot 3^{-1} = 5 \cdot \frac{1}{3} = \frac{5}{3} \]
So the model \( f(x) = 5 \cdot 3^x \) is appropriate, and at \( x = -1 \), the function evaluates to:
\[ f(-1) = \frac{5}{3} \]
Thus, the selected response:
**f(x) = 5⋅3^x; f(−1) = 5/3**
| x-Values | y-Values |
|----------|----------|
| 0 | 5 |
| 1 | 15 |
| 2 | 45 |
| 3 | 135 |
| 4 | 405 |
From observing the values, we can see that:
- \( y(0) = 5 \)
- \( y(1) = 15 = 5 \cdot 3 \)
- \( y(2) = 45 = 5 \cdot 3^2 \)
- \( y(3) = 135 = 5 \cdot 3^3 \)
- \( y(4) = 405 = 5 \cdot 3^4 \)
This suggests that the function could be modeled by the equation \( f(x) = 5 \cdot 3^x \).
Now, let's confirm if this function fits and calculate \( f(-1) \):
\[ f(-1) = 5 \cdot 3^{-1} = 5 \cdot \frac{1}{3} = \frac{5}{3} \]
So the model \( f(x) = 5 \cdot 3^x \) is appropriate, and at \( x = -1 \), the function evaluates to:
\[ f(-1) = \frac{5}{3} \]
Thus, the selected response:
**f(x) = 5⋅3^x; f(−1) = 5/3**
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