Question

A circular swimming pool has a radius of 15 ft. There is a path all the way around that pool that is three feet wide. What is the circumference of the outer edge of the path around the pool? Use 3.14 for r.

Answers

GPT-4o mini
To calculate the circumference of the outer edge of the path around the pool, we first need to determine the radius of the entire structure, which includes both the pool and the path.

1. The radius of the swimming pool is given as 15 feet.
2. The width of the path around the pool is 3 feet.
3. Therefore, the radius of the outer edge of the path is:

\[
15 \text{ ft (radius of pool)} + 3 \text{ ft (width of path)} = 18 \text{ ft}
\]

Next, we can use the formula for the circumference of a circle, which is

\[
C = 2 \pi r
\]

Substituting in \( r = 18 \) feet and using \( \pi \approx 3.14 \):

\[
C = 2 \times 3.14 \times 18
\]

Calculating this step by step:

1. Calculate \( 2 \times 3.14 \):

\[
2 \times 3.14 = 6.28
\]

2. Now multiply \( 6.28 \) by \( 18 \):

\[
C = 6.28 \times 18 = 113.04
\]

Thus, the circumference of the outer edge of the path around the pool is

\[
\boxed{113.04 \text{ ft}}
\]