Question

The mean absolute deviation of Dataset #1 is 48.2. Dataset #2 follows. Which dataset is more spread out?

Dataset #2: 401, 467, 489, 503, 568

(1 point)

Dataset #2 is more spread out because it has a mean absolute deviation of 41.28, whereas Dataset #1 has a mean absolute deviation of 48.2

Dataset #1 is more spread out because it has a mean absolute deviation of 48.2 whereas Dataset 2 has a mean absolute deviation of 41.25

Dataset #2 is more spread out because it has a mean absolute deviation of 485.6 whereas Dataset #1 has a mean absolute deviation of only 48.2

Dataset #1 is more spread out because it has a mean absolute devotion of 48.2 whereas Dataset 2 has a mean absolute deviation of 0.

Answer 1

To determine which dataset is more spread out, we can compare their mean absolute deviations (MAD).

- Dataset #1 has a mean absolute deviation of 48.2.
- Dataset #2 has a mean absolute deviation of 41.28.

Since the mean absolute deviation is a measure of spread, the dataset with the higher MAD is more spread out. Therefore, since 48.2 (Dataset #1) is greater than 41.28 (Dataset #2), we conclude:

**Dataset #1 is more spread out because it has a mean absolute deviation of 48.2 whereas Dataset #2 has a mean absolute deviation of 41.28.**

So, the correct option is:
**Dataset #1 is more spread out because it has a mean absolute deviation of 48.2 whereas Dataset #2 has a mean absolute deviation of 41.28.**

(Please note that none of the given options in your query exactly match this, but this is the accurate conclusion based on the data provided.)