Question
Rachel is a stunt driver, and she's escaping from a building that is about to explode!
The variable
models Rachel's distance from her exit (in meters)
seconds after the cameras began recording the stunt.
d=-38t+220
The variable
models Rachel's distance from her exit (in meters)
seconds after the cameras began recording the stunt.
d=-38t+220
Answers
GPT-4o mini
The equation provided, \( d = -38t + 220 \), models Rachel's distance from her exit over time while she's driving. Here, \( d \) represents the distance in meters from the exit, and \( t \) represents time in seconds.
To interpret this equation:
- The term \(-38t\) indicates that Rachel's distance from the exit is decreasing at a rate of 38 meters per second, which means she is driving towards her exit.
- The constant \(220\) in the equation indicates that she starts at a distance of 220 meters from the exit when \( t = 0 \).
To find out how long it will take Rachel to reach the exit (when \( d = 0 \)), we can set the equation to zero and solve for \( t \):
\[
0 = -38t + 220
\]
Rearranging the equation gives us:
\[
38t = 220
\]
Now, dividing both sides by \( 38 \):
\[
t = \frac{220}{38} \approx 5.79 \text{ seconds}
\]
Thus, Rachel will reach her exit in approximately **5.79 seconds**.
To interpret this equation:
- The term \(-38t\) indicates that Rachel's distance from the exit is decreasing at a rate of 38 meters per second, which means she is driving towards her exit.
- The constant \(220\) in the equation indicates that she starts at a distance of 220 meters from the exit when \( t = 0 \).
To find out how long it will take Rachel to reach the exit (when \( d = 0 \)), we can set the equation to zero and solve for \( t \):
\[
0 = -38t + 220
\]
Rearranging the equation gives us:
\[
38t = 220
\]
Now, dividing both sides by \( 38 \):
\[
t = \frac{220}{38} \approx 5.79 \text{ seconds}
\]
Thus, Rachel will reach her exit in approximately **5.79 seconds**.