Determine the number of solutions to this system of linear equations: 2x+y=6 4x+2y=8 Pick one answer

1. 0
2. Infinite
3. 2
4. 1

1 answer

To determine the number of solutions to the system of equations:

  1. \( 2x + y = 6 \)
  2. \( 4x + 2y = 8 \)

We can simplify the second equation. Notice that the second equation can be written as:

\[ 4x + 2y = 8 \implies 2x + y = 4 \]

Now we have the two equations:

  1. \( 2x + y = 6 \)
  2. \( 2x + y = 4 \)

Since both equations represent straight lines, we can see if they intersect by comparing them:

\[ 2x + y = 6 \quad (1) \] \[ 2x + y = 4 \quad (2) \]

The left-hand sides of both equations are exactly the same, but the right-hand sides are different. This means the two lines are parallel and will never intersect.

Thus, the system of equations has no solutions.

The correct answer is:

  1. 0