Asked by Noid
Da ages, in years of randomly selected employees r 34, 41, 38, 35, 37,44, 48, 29, 33, and 39. Determine da mean age
A ) 37.8
B ) 39.8
C ) 35.8
D ) 36.8
A ) 37.8
B ) 39.8
C ) 35.8
D ) 36.8
Answers
Answered by
GPT-4o mini
To determine the mean age, we need to sum all the ages and then divide by the number of ages.
The ages are: 34, 41, 38, 35, 37, 44, 48, 29, 33, and 39.
1. First, calculate the sum of ages:
\( 34 + 41 + 38 + 35 + 37 + 44 + 48 + 29 + 33 + 39 \)
Sum = 34 + 41 + 38 + 35 + 37 + 44 + 48 + 29 + 33 + 39 = 408
2. Next, count the number of employees:
There are 10 ages.
3. Now calculate the mean:
Mean = Total Sum / Number of values = \( \frac{408}{10} = 40.8 \)
However, it seems we made an error considering our sum calculation. Let’s redo the addition:
- \( 34 + 41 = 75 \)
- \( 75 + 38 = 113 \)
- \( 113 + 35 = 148 \)
- \( 148 + 37 = 185 \)
- \( 185 + 44 = 229 \)
- \( 229 + 48 = 277 \)
- \( 277 + 29 = 306 \)
- \( 306 + 33 = 339 \)
- \( 339 + 39 = 378 \)
Now we have the correct sum: \( 378 \).
Now, divide this by the number of employees:
Mean = \( \frac{378}{10} = 37.8 \).
So the mean age is:
**A) 37.8**.
The ages are: 34, 41, 38, 35, 37, 44, 48, 29, 33, and 39.
1. First, calculate the sum of ages:
\( 34 + 41 + 38 + 35 + 37 + 44 + 48 + 29 + 33 + 39 \)
Sum = 34 + 41 + 38 + 35 + 37 + 44 + 48 + 29 + 33 + 39 = 408
2. Next, count the number of employees:
There are 10 ages.
3. Now calculate the mean:
Mean = Total Sum / Number of values = \( \frac{408}{10} = 40.8 \)
However, it seems we made an error considering our sum calculation. Let’s redo the addition:
- \( 34 + 41 = 75 \)
- \( 75 + 38 = 113 \)
- \( 113 + 35 = 148 \)
- \( 148 + 37 = 185 \)
- \( 185 + 44 = 229 \)
- \( 229 + 48 = 277 \)
- \( 277 + 29 = 306 \)
- \( 306 + 33 = 339 \)
- \( 339 + 39 = 378 \)
Now we have the correct sum: \( 378 \).
Now, divide this by the number of employees:
Mean = \( \frac{378}{10} = 37.8 \).
So the mean age is:
**A) 37.8**.
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