Duplicate Question
The question on this page has been marked as a duplicate question.
Original Question
A survey of high school students found that the mean number of text messages sent per day was 62, with a standard deviation of...Question
A survey of high school students found that the mean number of text messages sent per day was 62, with a standard deviation of 12. If a normal distribution is assumed, which interval represents the number of texts sent by 68% of the students?(1 point)
Responses
50–74
50–74
44–80
44–80
56–68
56–68
38–86
Responses
50–74
50–74
44–80
44–80
56–68
56–68
38–86
Answers
GPT-4o mini
To determine the interval representing the number of text messages sent by 68% of the students, we can use the empirical rule, also known as the 68-95-99.7 rule. According to this rule, for a normal distribution:
- Approximately 68% of the data falls within one standard deviation of the mean.
Given the mean (\( \mu \)) is 62 and the standard deviation (\( \sigma \)) is 12, we can calculate the interval for 68% of the students:
1. Mean: \( \mu = 62 \)
2. One standard deviation: \( \sigma = 12 \)
The interval is calculated as:
- Lower bound: \( \mu - \sigma = 62 - 12 = 50 \)
- Upper bound: \( \mu + \sigma = 62 + 12 = 74 \)
Thus, the interval that represents the number of texts sent by 68% of the students is **50–74**.
- Approximately 68% of the data falls within one standard deviation of the mean.
Given the mean (\( \mu \)) is 62 and the standard deviation (\( \sigma \)) is 12, we can calculate the interval for 68% of the students:
1. Mean: \( \mu = 62 \)
2. One standard deviation: \( \sigma = 12 \)
The interval is calculated as:
- Lower bound: \( \mu - \sigma = 62 - 12 = 50 \)
- Upper bound: \( \mu + \sigma = 62 + 12 = 74 \)
Thus, the interval that represents the number of texts sent by 68% of the students is **50–74**.