Question 1
To determine if the events of selecting activities for each of the Saturdays are independent or dependent probabilities, you would need to observe how the selection of one activity affects the selection of another. Specifically, you would:
- Draw the first activity from the cup and note it down.
- Without replacing the first slip back into the cup, draw the second activity.
- Note whether the first drawing affects your choices for the second activity.
- Repeat this process for all four Saturdays, assessing at each step whether the remaining choices are influenced by past selections.
If drawing one activity changes the outcomes available for subsequent selections, the events are dependent. If every selection is unaffected by the previous draws (which would require replacement), the events are independent.
Question 2
If bowling is picked as the first activity, there are three remaining activities: the movies, skating, and the arcade. The number of permutations of these three activities can be calculated as 3!, which is 3 factorial.
3! = 3 × 2 × 1 = 6 permutations.
The possible arrangements of the remaining activities following bowling are:
- Bowling, Movies, Skating, Arcade
- Bowling, Movies, Arcade, Skating
- Bowling, Skating, Movies, Arcade
- Bowling, Skating, Arcade, Movies
- Bowling, Arcade, Movies, Skating
- Bowling, Arcade, Skating, Movies
Thus, those are the six possible permutations for the remaining events after selecting bowling first.