Sure! Here are the answers to your questions:
Question 1: Emilio rolls a typical 6-sided number cube. The possible outcomes for him to roll an even number that is divisible by 3 are only {6}.
Question 2: You have two rolls knocking down pins: {2,3,5,10} and {6,7}. The total pins are {1,2,3,4,5,6,7,8,9,10}. The complement of event (knocking down the selected pins) contains the pins that were not knocked down, which are {1,4,8,9}. Therefore, the answer is Option #3: {1,4,8,9}.
Question 3: In a standard deck of cards, there are 2 red 7s (one from diamonds and one from hearts). Thus, the probability of drawing a red 7 is 2/52, which simplifies to 1/26.
Question 4: Event A (spinner numbers greater than 3) results in {4, 5, 6, 7, 8} which has 5 favorable outcomes. Event B (cube numbers greater than 3) results in {4, 5, 6} which has 3 favorable outcomes. By multiplying probabilities: P(A) = 5/8 P(B) = 3/6 = 1/2 P(A∩B) = P(A) * P(B) = (5/8) * (1/2) = 5/16.
Question 5: A)
- P(A ∩ B): There are 2 aces that are red. Probability = 2/52 = 1/26.
- P(A): There are 4 aces in total. Probability = 4/52 = 1/13.
- P(B): There are 26 red cards in total. Probability = 26/52 = 1/2.
B) True. Events A and B are dependent since knowing that a red card is drawn changes the probability of drawing an ace.
Question 6: The probability of drawing a red marble first (4 red out of 20) is 4/20. If a red marble is drawn, then there are 19 marbles left where the probability of drawing a green marble next (4 out of 19) is 4/19. Therefore, the combined probability is: P(red then green) = (4/20) * (4/19) = 16/380 = 4/95.
Question 7: A) The probability of selecting a historical fiction book (12 out of 50) and then a romance novel (8 out of 49) is: P = (12/50) * (8/49) = 96/2450 = 48/1225.
B) For selecting a nonfiction book (15 out of 50) first and then a mystery novel (15 out of 49): P = (15/50) * (15/49) = 225/2450 = 45/490.
Question 8: A) The total ways to allocate prizes to 20 athletes (permutations) is: P(20,5) = 20! / (20-5)! = 20! / 15! = 20 * 19 * 18 * 17 * 16 = 1860480.
B) If only 10 people enter, the ways to allocate prizes is: P(10,5) = 10! / (10-5)! = 10! / 5! = 10 * 9 * 8 * 7 * 6 = 30240.
Question 9: A) To choose 5 books from 24 without regard to order, you would compute combinations. \( C(24,5) \): C(24,5) = 24!/(5!(24-5)!) = 42504. So, the answer is 42504.
B) If order matters, you would use permutations: P(24,5) = 24! / (24-5)! = 24 * 23 * 22 * 21 * 20 = 42504.
Question 10: For the probability that a random point in the figure (trapezoid) is inside the circle inscribed within it, this depends on the ratio of the area of the circle to the area of the trapezoid. If we don't have specific measurements or ratios, an estimate of the probability could be given; let's say 0.24 (assuming based on some geometrical intuition).
If you have any follow-up questions or need clarifications, feel free to ask!