Question
n a class of students, the following data table summarizes how many students have a brother or a sister. What is the probability that a student who does not have a sister has a brother?
Has a brother Does not have a brother
Has a sister 4 9
Does not have a sister 2 15
Has a brother Does not have a brother
Has a sister 4 9
Does not have a sister 2 15
Answers
GPT-4o mini
To find the probability that a student who does not have a sister has a brother, we need to look at the relevant data from the table.
From the table:
- Students who **do not have a sister** and **have a brother**: 2
- Students who **do not have a sister** and **do not have a brother**: 15
Now, we will calculate the total number of students who **do not have a sister**:
Total (do not have a sister) = 2 (have a brother) + 15 (do not have a brother) = 17
Now, we want the probability that a student who does not have a sister has a brother. This probability can be calculated as follows:
\[
P(\text{has a brother} \mid \text{does not have a sister}) = \frac{\text{Number of students who do not have a sister but have a brother}}{\text{Total number of students who do not have a sister}} = \frac{2}{17}
\]
Thus, the probability that a student who does not have a sister has a brother is:
\[
\frac{2}{17}
\]
From the table:
- Students who **do not have a sister** and **have a brother**: 2
- Students who **do not have a sister** and **do not have a brother**: 15
Now, we will calculate the total number of students who **do not have a sister**:
Total (do not have a sister) = 2 (have a brother) + 15 (do not have a brother) = 17
Now, we want the probability that a student who does not have a sister has a brother. This probability can be calculated as follows:
\[
P(\text{has a brother} \mid \text{does not have a sister}) = \frac{\text{Number of students who do not have a sister but have a brother}}{\text{Total number of students who do not have a sister}} = \frac{2}{17}
\]
Thus, the probability that a student who does not have a sister has a brother is:
\[
\frac{2}{17}
\]