Question

In which situation did the car achieve the greatest efficiency? (Assume the cars all have the same mass.)(1 point)
Responses

a car that traveled 70 kilometers on 5.0 liters of gas
a car that traveled 70 kilometers on 5.0 liters of gas

a car that traveled 50 kilometers on 4.0 liters of gas
a car that traveled 50 kilometers on 4.0 liters of gas

a car that traveled 90 kilometers on 6.0 liters of gas
a car that traveled 90 kilometers on 6.0 liters of gas

a car that traveled 80 kilometers on 5.0 liters of gas
a car that traveled 80 kilometers on 5.0 liters of gas

Answer 1

To determine which car achieved the greatest efficiency, we can calculate the fuel efficiency (in kilometers per liter) for each of the situations provided.

1. For the first car:
- Distance: 70 kilometers
- Fuel: 5.0 liters
- Efficiency = Distance / Fuel = 70 km / 5.0 L = 14 km/L

2. For the second car:
- Distance: 50 kilometers
- Fuel: 4.0 liters
- Efficiency = Distance / Fuel = 50 km / 4.0 L = 12.5 km/L

3. For the third car:
- Distance: 90 kilometers
- Fuel: 6.0 liters
- Efficiency = Distance / Fuel = 90 km / 6.0 L = 15 km/L

4. For the fourth car:
- Distance: 80 kilometers
- Fuel: 5.0 liters
- Efficiency = Distance / Fuel = 80 km / 5.0 L = 16 km/L

Now we can compare the efficiencies:
- Car 1: 14 km/L
- Car 2: 12.5 km/L
- Car 3: 15 km/L
- Car 4: 16 km/L

The car that achieved the greatest efficiency is **the fourth car**, which traveled 80 kilometers on 5.0 liters of gas, resulting in an efficiency of **16 km/L**.