To determine which table represents a quadratic relationship between \(x\) and \(y\), we can look for a relationship where the second differences of \(y\) values (as \(x\) values change) are constant. A quadratic relationship generally follows the form \(y = ax^2 + bx + c\).
Let's analyze each table:
Table A:
x y
-2 ?
-1 1/4
0 1
1 4
2 16
We cannot compute differences because not all \(y\) values are given.
Table B:
x y
-2 8
-1 4
0 0
1 4
2 8
First differences:
- From -2 to -1: \(4 - 8 = -4\)
- From -1 to 0: \(0 - 4 = -4\)
- From 0 to 1: \(4 - 0 = 4\)
- From 1 to 2: \(8 - 4 = 4\)
Second differences:
- From -4 to -4: \( -4 - (-4) = 0 \)
- From -4 to 4: \( 4 - (-4) = 8 \)
- From 4 to 4: \( 4 - 4 = 0 \)
Not constant.
Table C:
x y
-2 -8
-1 -1
0 0
1 1
2 8
First differences:
- From -2 to -1: \(-1 - (-8) = 7\)
- From -1 to 0: \(0 - (-1) = 1\)
- From 0 to 1: \(1 - 0 = 1\)
- From 1 to 2: \(8 - 1 = 7\)
Second differences:
- From 7 to 1: \(1 - 7 = -6\)
- From 1 to 1: \(1 - 1 = 0\)
- From 1 to 7: \(7 - 1 = 6\)
Not constant.
Table D:
x y
-2 -4
-1 -1
0 0
1 1
2 4
First differences:
- From -2 to -1: \(-1 - (-4) = 3\)
- From -1 to 0: \(0 - (-1) = 1\)
- From 0 to 1: \(1 - 0 = 1\)
- From 1 to 2: \(4 - 1 = 3\)
Second differences:
- From 3 to 1: \(1 - 3 = -2\)
- From 1 to 1: \(1 - 1 = 0\)
- From 1 to 3: \(3 - 1 = 2\)
Not constant.
Table E:
x y
-2 5
-1 2
0 1
1 2
2 5
First differences:
- From -2 to -1: \(2 - 5 = -3\)
- From -1 to 0: \(1 - 2 = -1\)
- From 0 to 1: \(2 - 1 = 1\)
- From 1 to 2: \(5 - 2 = 3\)
Second differences:
- From -3 to -1: \(-1 - (-3) = 2\)
- From -1 to 1: \(1 - (-1) = 2\)
- From 1 to 3: \(3 - 1 = 2\)
The second differences are constant here.
Thus, the answer is:
E. Table E