Points p and q are negative integers plotted on a number line.

If |p| > |g|, which statement is true?
• A. Point p is further from 0 than point q, and to the right of point q.
O B. Point is closer to 0 than point q, and to the right of point q.
O c. Point is closer to 0 than point q, and to the left of point q.
• D. Point p is further from 0 than point q, and to the left of point q.

1 answer

To solve the problem, we need to analyze the given condition and the statements in the context of negative integers.

The notation |p| and |q| represents the absolute values of p and q, respectively. Since p and q are both negative integers, their absolute values are positive. The condition |p| > |q| means that the absolute value of p is greater than the absolute value of q.

This implies that:

  • If |p| > |q|, then p must be a larger negative number than q. For instance, if p = -4 and q = -2, then |p| = 4 and |q| = 2, satisfying |p| > |q|.

Next, we identify how these numbers are positioned on the number line:

  1. Negative integers are positioned to the left of zero. The further away from zero (i.e., the more negative the number), the further left on the number line it will be.
  2. Since |p| > |q| means p is further away from zero (more negative) than q, it follows that p is to the left of q on the number line.

Now, let's evaluate the statements provided:

A. Point p is further from 0 than point q, and to the right of point q. (False, because p is to the left of q.) B. Point p is closer to 0 than point q, and to the right of point q. (False, because p is further from 0 and is to the left of q.) C. Point p is closer to 0 than point q, and to the left of point q. (False, because p is further from 0.) D. Point p is further from 0 than point q, and to the left of point q. (True, this is correct.)

Thus, the correct statement is:

D. Point p is further from 0 than point q, and to the left of point q.