Question

Plot the image of point Q

under the translation (x,y)----> (x-3,y + 4)

.y up , x ----->x

Answer 1

To plot the image of point \( Q \) under the given translation \( (x,y) \rightarrow (x-3, y + 4) \), follow these steps:

1. **Identify the Original Point \( Q \)**: Let's say \( Q \) has coordinates \( (x_Q, y_Q) \). For example, let us assume \( Q = (2, 1) \).

2. **Apply the Translation**:
- According to the translation rule:
\[
Q' = (x_Q - 3, y_Q + 4)
\]
- Substituting our assumed coordinates:
\[
Q' = (2 - 3, 1 + 4) = (-1, 5)
\]

3. **Plot the Points**:
- **Original Point \( Q \)**: Plot the point \( (2, 1) \).
- **Translated Point \( Q' \)**: Plot the point \( (-1, 5) \).

4. **Graph**:
- On a Cartesian coordinate system, mark the original point \( Q \) at the coordinates \( (2, 1) \) and the translated point \( Q' \) at \( (-1, 5) \). Draw a vector from \( Q \) to \( Q' \) to illustrate the translation.

If you have specific coordinates for point \( Q \), please provide them, and I can calculate the translated coordinates accordingly!