Plot the image of point Q


under the translation (x,y)----> (x-3,y + 4)

.y up , x ----->x

1 answer

To plot the image of point \( Q \) under the given translation \( (x,y) \rightarrow (x-3, y + 4) \), follow these steps:

  1. Identify the Original Point \( Q \): Let's say \( Q \) has coordinates \( (x_Q, y_Q) \). For example, let us assume \( Q = (2, 1) \).

  2. Apply the Translation:

    • According to the translation rule: \[ Q' = (x_Q - 3, y_Q + 4) \]
    • Substituting our assumed coordinates: \[ Q' = (2 - 3, 1 + 4) = (-1, 5) \]
  3. Plot the Points:

    • Original Point \( Q \): Plot the point \( (2, 1) \).
    • Translated Point \( Q' \): Plot the point \( (-1, 5) \).
  4. Graph:

    • On a Cartesian coordinate system, mark the original point \( Q \) at the coordinates \( (2, 1) \) and the translated point \( Q' \) at \( (-1, 5) \). Draw a vector from \( Q \) to \( Q' \) to illustrate the translation.

If you have specific coordinates for point \( Q \), please provide them, and I can calculate the translated coordinates accordingly!