Question

Find the sum of minus, 6, x, squared, plus, 3−6x
2
+3 and 4, x, squared, minus, 2, x4x
2
−2x.

Answer 1

To find the sum of the two expressions \(-6x^2 + 3\) and \(4x^2 - 2x\), we will combine like terms.

1. The first expression is:
\[
-6x^2 + 3
\]

2. The second expression is:
\[
4x^2 - 2x
\]

Now we will add these two expressions together:
\[
(-6x^2 + 3) + (4x^2 - 2x)
\]

Next, we will combine like terms:
- Combine the \(x^2\) terms: \(-6x^2 + 4x^2 = -2x^2\)
- Combine the \(x\) terms: There is only \(-2x\)
- Combine the constant terms: The constant is \(3\)

Putting it all together, we get:
\[
-2x^2 - 2x + 3
\]

Thus, the sum of the expressions \(-6x^2 + 3\) and \(4x^2 - 2x\) is:
\[
\boxed{-2x^2 - 2x + 3}
\]