Which polar equation represents an ellipse?

(1 point)
Responses

lower r equals start fraction 3 over 2 minus 5 sine theta end fraction
Image with alt text: lower r equals start fraction 3 over 2 minus 5 sine theta end fraction

lower r equals start fraction 2 over 2 minus sine theta end fraction
Image with alt text: lower r equals start fraction 2 over 2 minus sine theta end fraction

lower r equals start fraction 4 over 3 plus 3 cosine theta end fraction
Image with alt text: lower r equals start fraction 4 over 3 plus 3 cosine theta end fraction

lower r equals start fraction 5 over 3 plus 4 cosine theta end fraction

1 answer

To determine which polar equation represents an ellipse, we can refer to the standard forms of conic sections in polar coordinates. An ellipse can be represented in polar coordinates as:

\[ r = \frac{ed}{1 - e \cos \theta} \]

or

\[ r = \frac{ed}{1 - e \sin \theta} \]

where \(e\) (the eccentricity) is less than 1.

Analyzing the provided options:

  1. \( r = \frac{3}{2 - 5 \sin \theta} \)

    • Here, the denominator matches the form \(1 - e\sin \theta\), but \(5 > 2\), which means \(e = \frac{5}{2} > 1\), indicating that this is not an ellipse.
  2. \( r = \frac{2}{2 - \sin \theta} \)

    • This equation can be rewritten as \( r = \frac{2}{1 - \frac{1}{2} \sin \theta} \). So here, \( e = \frac{1}{2} < 1\), indicating that this is indeed an ellipse.
  3. \( r = \frac{4}{3 + 3 \cos \theta} \)

    • This form can be rearranged to \(r = \frac{4}{1 + \frac{3}{4} \cos \theta}\). Here, \( e = -\frac{3}{4} \), which does not define an ellipse since \(e\) should be positive.
  4. \( r = \frac{5}{3 + 4 \cos \theta} \)

    • Similarly, this can be represented as \(r = \frac{5}{1 + \frac{4}{5} \cos \theta}\); here \( e = -\frac{4}{5} \), which again does not represent an ellipse.

Thus, the polar equation that represents an ellipse is:

\( r = \frac{2}{2 - \sin \theta} \).