To find the equation of the linear function in the form \(y = mx + b\), we need to determine the slope \(m\) and the y-intercept \(b\).
First, we calculate the slope \(m\) using the two points given in the table: \((6, 16)\) and \((15, 43)\).
The formula for the slope \(m\) is:
\[ m = \frac{y_2 - y_1}{x_2 - x_1} \]
Plugging in the values:
\[ m = \frac{43 - 16}{15 - 6} = \frac{27}{9} = 3 \]
Now that we have the slope, \(m = 3\), we can use one of the points to find \(b\). We'll use the point \((6, 16)\).
The equation \(y = mx + b\) becomes:
\[ 16 = 3(6) + b \]
Calculating this gives:
\[ 16 = 18 + b \]
To solve for \(b\), we subtract 18 from both sides:
\[ b = 16 - 18 = -2 \]
Now we have both \(m\) and \(b\). Thus, the equation of the linear function is:
\[ y = 3x - 2 \]