Let's denote Jesse's total pocket money as \( P \).
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On Monday, he spends \( \frac{1}{2}P \).
- Remaining pocket money after Monday: \[ P - \frac{1}{2}P = \frac{1}{2}P \]
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On Tuesday, he spends \( \frac{2}{3} \) of what is left, which is \( \frac{2}{3} \times \frac{1}{2}P = \frac{1}{3}P \).
- Remaining pocket money after Tuesday: \[ \frac{1}{2}P - \frac{1}{3}P \] To subtract these fractions, we need a common denominator, which is 6: \[ \frac{1}{2}P = \frac{3}{6}P \quad \text{and} \quad \frac{1}{3}P = \frac{2}{6}P \] So: \[ \frac{3}{6}P - \frac{2}{6}P = \frac{1}{6}P \]
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On Wednesday, he spends \( \frac{1}{4} \) of what remains: \[ \frac{1}{4} \times \frac{1}{6}P = \frac{1}{24}P \]
- Remaining pocket money after Wednesday: \[ \frac{1}{6}P - \frac{1}{24}P \] Again, we need a common denominator to subtract, which is 24: \[ \frac{1}{6}P = \frac{4}{24}P \quad \text{and} \quad \frac{1}{24}P = \frac{1}{24}P \] So: \[ \frac{4}{24}P - \frac{1}{24}P = \frac{3}{24}P = \frac{1}{8}P \]
Finally, Jesse has \( \frac{1}{8} \) of his pocket money left.
The most reasonable answer is \( \frac{1}{8} \).