To find the probability of rolling an odd number on the first roll of a six-sided die and then rolling an even number on the second roll, we can break down the problem:
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Rolling an odd number on the first roll:
- The odd numbers on a six-sided die are 1, 3, and 5.
- There are 3 odd numbers out of 6 total numbers.
- Therefore, the probability of rolling an odd number is \( \frac{3}{6} = \frac{1}{2} \).
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Rolling an even number on the second roll:
- The even numbers on a six-sided die are 2, 4, and 6.
- There are 3 even numbers out of 6 total numbers.
- Therefore, the probability of rolling an even number is also \( \frac{3}{6} = \frac{1}{2} \).
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Calculating the combined probability:
- The two events (rolling an odd number first and rolling an even number second) are independent, so we multiply the probabilities: \[ P(\text{odd first}) \times P(\text{even second}) = \frac{1}{2} \times \frac{1}{2} = \frac{1}{4}. \]
Therefore, the answer is B) 1/4.