Question

Wut is da probability of rolling an odd number on da first roll of a six-sidded cube n rolling an even number on da sec roll?

A ) 1

B ) 1/4

C ) 2

D ) 1/3

Answer 1

To solve this probability problem, we need to analyze two parts: the probability of rolling an odd number on the first roll of a six-sided die and the probability of rolling an even number on the second roll.

1. **Calculating the probability of rolling an odd number on the first roll:**
- The odd numbers on a six-sided die are 1, 3, and 5.
- There are 3 odd numbers out of a total of 6 possible outcomes.
- Thus, the probability of rolling an odd number is:
\[
P(\text{odd}) = \frac{3}{6} = \frac{1}{2}
\]

2. **Calculating the probability of rolling an even number on the second roll:**
- The even numbers on a six-sided die are 2, 4, and 6.
- There are also 3 even numbers out of a total of 6 possible outcomes.
- Thus, the probability of rolling an even number is:
\[
P(\text{even}) = \frac{3}{6} = \frac{1}{2}
\]

3. **Calculating the combined probability:**
Since the rolls are independent, we can multiply the probabilities of the two events:
\[
P(\text{odd on first roll and even on second roll}) = P(\text{odd}) \times P(\text{even}) = \frac{1}{2} \times \frac{1}{2} = \frac{1}{4}
\]

Therefore, the probability of rolling an odd number on the first roll and an even number on the second roll is \(\frac{1}{4}\).

The correct answer is **B) 1/4**.