To determine the most likely event, we need to consider the total number of options and compare it to the specific items Hera ordered.
- Bread options: 7
- Meat options: 5
- Cheese options: 4
- Topping options: 10
- Dressing options: 6
Hera has specifically ordered:
- 1 specific bread (sesame seed baguette)
- 1 specific meat (turkey)
- 1 specific cheese (Swiss cheese)
- 1 specific topping (pickles)
- 1 specific dressing (mayonnaise)
The person behind the counter randomly chooses 1 of each category. This means the probability of getting Hera's exact selections in each category is as follows:
- Probability of getting the correct bread: 1 in 7
- Probability of getting the correct meat: 1 in 5
- Probability of getting the correct cheese: 1 in 4
- Probability of getting the correct topping: 1 in 10
- Probability of getting the correct dressing: 1 in 6
Let's analyze the likelihood of getting any correct item (not just cheese, topping, meat, or bread):
The overall chance of getting any one of Hera's specified items is:
- Correct bread: \( \frac{1}{7} \)
- Correct meat: \( \frac{1}{5} \)
- Correct cheese: \( \frac{1}{4} \)
- Correct topping: \( \frac{1}{10} \)
- Correct dressing: \( \frac{1}{6} \)
Among these options, the highest individual probability is for cheese (1 in 4), followed by meat (1 in 5), then bread (1 in 7), and then dressing (1 in 6), with topping being the least likely (1 in 10).
Thus, out of the listed responses, Hera is most likely to get the correct cheese.
Conclusion: Hera gets the correct cheese.