Question
Solve the system by Substitution.
y = 2x + 5
3x - 4y = 10(1 point)
Responses
(5,2)
(5,2)
(-6, -7)
(-6, -7)
(-2,1)
y = 2x + 5
3x - 4y = 10(1 point)
Responses
(5,2)
(5,2)
(-6, -7)
(-6, -7)
(-2,1)
Answers
Answered by
GPT-4o mini
To solve the system of equations using substitution, we start with the two equations given:
1. \( y = 2x + 5 \)
2. \( 3x - 4y = 10 \)
Since we already have \( y \) expressed in terms of \( x \) from the first equation, we can substitute this expression for \( y \) into the second equation.
Substituting \( y = 2x + 5 \) into the second equation:
\[
3x - 4(2x + 5) = 10
\]
Now distribute the -4:
\[
3x - 8x - 20 = 10
\]
Combine like terms:
\[
-5x - 20 = 10
\]
Now, isolate \( x \):
\[
-5x = 10 + 20
\]
\[
-5x = 30
\]
\[
x = -6
\]
Now that we have \( x \), we substitute it back into the first equation to solve for \( y \):
\[
y = 2(-6) + 5
\]
\[
y = -12 + 5
\]
\[
y = -7
\]
So the solution to the system of equations is:
\[
(x, y) = (-6, -7)
\]
Thus, the answer is:
**(-6, -7)**
1. \( y = 2x + 5 \)
2. \( 3x - 4y = 10 \)
Since we already have \( y \) expressed in terms of \( x \) from the first equation, we can substitute this expression for \( y \) into the second equation.
Substituting \( y = 2x + 5 \) into the second equation:
\[
3x - 4(2x + 5) = 10
\]
Now distribute the -4:
\[
3x - 8x - 20 = 10
\]
Combine like terms:
\[
-5x - 20 = 10
\]
Now, isolate \( x \):
\[
-5x = 10 + 20
\]
\[
-5x = 30
\]
\[
x = -6
\]
Now that we have \( x \), we substitute it back into the first equation to solve for \( y \):
\[
y = 2(-6) + 5
\]
\[
y = -12 + 5
\]
\[
y = -7
\]
So the solution to the system of equations is:
\[
(x, y) = (-6, -7)
\]
Thus, the answer is:
**(-6, -7)**