A cube of steel has a mass of 1,000 kilograms. What are the dimensions of the cube if the density of steel is 8,000 kg/ m3 ?(1 point)

Responses

0.5 m
0.5 m

5 m
5 m

0.05 m
0.05 m

50 m

1 answer

To find the dimensions of a cube given its mass and density, you can use the formula for density:

\[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} \]

From this, you can rearrange the formula to find the volume (V):

\[ V = \frac{\text{Mass}}{\text{Density}} \]

In this case, the mass of the steel cube is 1,000 kg, and the density of steel is 8,000 kg/m³. Plugging in the values:

\[ V = \frac{1000 \text{ kg}}{8000 \text{ kg/m}^3} = 0.125 \text{ m}^3 \]

Since the cube's volume is also equal to \( \text{side}^3 \), we can find the length of one side (s) of the cube:

\[ s^3 = V \implies s = \sqrt[3]{V} \] \[ s = \sqrt[3]{0.125 \text{ m}^3} = 0.5 \text{ m} \]

The dimensions of the cube are \(0.5 , \text{m} \times 0.5 , \text{m} \times 0.5 , \text{m}\).

Thus, the correct response is:

0.5 m