Question
A steel cylinder has a base with a radius of 10 cm and height of 8 cm.
If the density of the cylinder is 0.008 kg/ cm3 , find the mass of the cylinder in kilograms.
Use π=3.14 and round your final answer to the nearest tenth.
(1 point)
Volume =
cm3
Mass =
kg
If the density of the cylinder is 0.008 kg/ cm3 , find the mass of the cylinder in kilograms.
Use π=3.14 and round your final answer to the nearest tenth.
(1 point)
Volume =
cm3
Mass =
kg
Answers
GPT-4o mini
To find the mass of the steel cylinder, we first need to calculate its volume and then use the density to find the mass.
1. **Calculate the volume of the cylinder** using the formula:
\[
\text{Volume} = \pi r^2 h
\]
where:
- \( r \) is the radius,
- \( h \) is the height.
Given:
- \( r = 10 \) cm,
- \( h = 8 \) cm,
- \( \pi \approx 3.14 \).
Substitute these values into the formula:
\[
\text{Volume} = 3.14 \times (10 \, \text{cm})^2 \times 8 \, \text{cm}
\]
\[
= 3.14 \times 100 \, \text{cm}^2 \times 8 \, \text{cm}
\]
\[
= 3.14 \times 800 \, \text{cm}^3
\]
\[
= 2512 \, \text{cm}^3
\]
2. **Calculate the mass** of the cylinder using the formula:
\[
\text{Mass} = \text{Density} \times \text{Volume}
\]
Given the density of the cylinder is \( 0.008 \, \text{kg/cm}^3 \):
\[
\text{Mass} = 0.008 \, \text{kg/cm}^3 \times 2512 \, \text{cm}^3
\]
\[
= 20.096 \, \text{kg}
\]
3. **Round the mass to the nearest tenth**:
The mass is approximately \( 20.1 \, \text{kg} \).
Thus, the answers are:
- Volume = **2512 cm³**
- Mass = **20.1 kg**
1. **Calculate the volume of the cylinder** using the formula:
\[
\text{Volume} = \pi r^2 h
\]
where:
- \( r \) is the radius,
- \( h \) is the height.
Given:
- \( r = 10 \) cm,
- \( h = 8 \) cm,
- \( \pi \approx 3.14 \).
Substitute these values into the formula:
\[
\text{Volume} = 3.14 \times (10 \, \text{cm})^2 \times 8 \, \text{cm}
\]
\[
= 3.14 \times 100 \, \text{cm}^2 \times 8 \, \text{cm}
\]
\[
= 3.14 \times 800 \, \text{cm}^3
\]
\[
= 2512 \, \text{cm}^3
\]
2. **Calculate the mass** of the cylinder using the formula:
\[
\text{Mass} = \text{Density} \times \text{Volume}
\]
Given the density of the cylinder is \( 0.008 \, \text{kg/cm}^3 \):
\[
\text{Mass} = 0.008 \, \text{kg/cm}^3 \times 2512 \, \text{cm}^3
\]
\[
= 20.096 \, \text{kg}
\]
3. **Round the mass to the nearest tenth**:
The mass is approximately \( 20.1 \, \text{kg} \).
Thus, the answers are:
- Volume = **2512 cm³**
- Mass = **20.1 kg**