determine which pair of functions are inverses functions
a.f(x)=x-4
g(x)=x+4
b.f(x)=x-4
g(x)=x-4/4
c.f(x)=x-4
g(x)=4x-1
a.f(x)=x-4
g(x)=x+4
b.f(x)=x-4
g(x)=x-4/4
c.f(x)=x-4
g(x)=4x-1
Answers
Answered by
GPT-4o mini
To determine whether two functions are inverse functions, we need to check if \( f(g(x)) = x \) and \( g(f(x)) = x \).
Let's analyze each pair:
### a.
- \( f(x) = x - 4 \)
- \( g(x) = x + 4 \)
Calculating \( f(g(x)) \):
\[
f(g(x)) = f(x + 4) = (x + 4) - 4 = x
\]
Calculating \( g(f(x)) \):
\[
g(f(x)) = g(x - 4) = (x - 4) + 4 = x
\]
Since both \( f(g(x)) = x \) and \( g(f(x)) = x \), **\( f(x) \) and \( g(x) \) are inverse functions**.
---
### b.
- \( f(x) = x - 4 \)
- \( g(x) = \frac{x - 4}{4} \)
Calculating \( f(g(x)) \):
\[
f(g(x)) = f\left(\frac{x - 4}{4}\right) = \frac{x - 4}{4} - 4 = \frac{x - 4 - 16}{4} = \frac{x - 20}{4}
\]
This is not equal to \( x \).
Calculating \( g(f(x)) \):
\[
g(f(x)) = g(x - 4) = \frac{(x - 4) - 4}{4} = \frac{x - 8}{4}
\]
This is also not equal to \( x \).
Thus, **\( f(x) \) and \( g(x) \) are not inverse functions**.
---
### c.
- \( f(x) = x - 4 \)
- \( g(x) = 4x - 1 \)
Calculating \( f(g(x)) \):
\[
f(g(x)) = f(4x - 1) = (4x - 1) - 4 = 4x - 5
\]
This is not equal to \( x \).
Calculating \( g(f(x)) \):
\[
g(f(x)) = g(x - 4) = 4(x - 4) - 1 = 4x - 16 - 1 = 4x - 17
\]
This is also not equal to \( x \).
Thus, **\( f(x) \) and \( g(x) \) are not inverse functions**.
### Conclusion:
The only pair of functions that are inverse functions is:
**a. \( f(x) = x - 4 \) and \( g(x) = x + 4 \)**.
Let's analyze each pair:
### a.
- \( f(x) = x - 4 \)
- \( g(x) = x + 4 \)
Calculating \( f(g(x)) \):
\[
f(g(x)) = f(x + 4) = (x + 4) - 4 = x
\]
Calculating \( g(f(x)) \):
\[
g(f(x)) = g(x - 4) = (x - 4) + 4 = x
\]
Since both \( f(g(x)) = x \) and \( g(f(x)) = x \), **\( f(x) \) and \( g(x) \) are inverse functions**.
---
### b.
- \( f(x) = x - 4 \)
- \( g(x) = \frac{x - 4}{4} \)
Calculating \( f(g(x)) \):
\[
f(g(x)) = f\left(\frac{x - 4}{4}\right) = \frac{x - 4}{4} - 4 = \frac{x - 4 - 16}{4} = \frac{x - 20}{4}
\]
This is not equal to \( x \).
Calculating \( g(f(x)) \):
\[
g(f(x)) = g(x - 4) = \frac{(x - 4) - 4}{4} = \frac{x - 8}{4}
\]
This is also not equal to \( x \).
Thus, **\( f(x) \) and \( g(x) \) are not inverse functions**.
---
### c.
- \( f(x) = x - 4 \)
- \( g(x) = 4x - 1 \)
Calculating \( f(g(x)) \):
\[
f(g(x)) = f(4x - 1) = (4x - 1) - 4 = 4x - 5
\]
This is not equal to \( x \).
Calculating \( g(f(x)) \):
\[
g(f(x)) = g(x - 4) = 4(x - 4) - 1 = 4x - 16 - 1 = 4x - 17
\]
This is also not equal to \( x \).
Thus, **\( f(x) \) and \( g(x) \) are not inverse functions**.
### Conclusion:
The only pair of functions that are inverse functions is:
**a. \( f(x) = x - 4 \) and \( g(x) = x + 4 \)**.