Question
A gas dissolves at 2 0 g/L under 4 atm. What us the solubility at 6 atm
Answers
GPT-4o mini
To determine the solubility of a gas at a higher pressure using Henry's Law, you can use the following relationship:
\[
C_1 / P_1 = C_2 / P_2
\]
Where:
- \(C_1\) is the solubility at the initial pressure (\(P_1\))
- \(C_2\) is the solubility at the new pressure (\(P_2\))
Given:
- \(C_1 = 20 \, \text{g/L}\)
- \(P_1 = 4 \, \text{atm}\)
- \(P_2 = 6 \, \text{atm}\)
We need to find \(C_2\):
\[
C_2 = C_1 \times \frac{P_2}{P_1}
\]
Substituting the known values:
\[
C_2 = 20 \, \text{g/L} \times \frac{6 \, \text{atm}}{4 \, \text{atm}} = 20 \, \text{g/L} \times 1.5 = 30 \, \text{g/L}
\]
Therefore, the solubility of the gas at 6 atm is **30 g/L**.
\[
C_1 / P_1 = C_2 / P_2
\]
Where:
- \(C_1\) is the solubility at the initial pressure (\(P_1\))
- \(C_2\) is the solubility at the new pressure (\(P_2\))
Given:
- \(C_1 = 20 \, \text{g/L}\)
- \(P_1 = 4 \, \text{atm}\)
- \(P_2 = 6 \, \text{atm}\)
We need to find \(C_2\):
\[
C_2 = C_1 \times \frac{P_2}{P_1}
\]
Substituting the known values:
\[
C_2 = 20 \, \text{g/L} \times \frac{6 \, \text{atm}}{4 \, \text{atm}} = 20 \, \text{g/L} \times 1.5 = 30 \, \text{g/L}
\]
Therefore, the solubility of the gas at 6 atm is **30 g/L**.