Asked by hrsdptmsgshch (supernatural)
A circle is traced along the circumference of a sphere at the center like a latitude. A dot is plotted at the center. The radius measures 5 feet.
What is the volume of the sphere using 3.14 for pi and rounded to the nearest tenth?
(1 point)
Responses
523.3 ft.3
523.3 ft. cubed
104.7 ft.3
104.7 ft. cubed
4,188.8 ft.3
4,188.8 ft. cubed
62.8 ft.3
What is the volume of the sphere using 3.14 for pi and rounded to the nearest tenth?
(1 point)
Responses
523.3 ft.3
523.3 ft. cubed
104.7 ft.3
104.7 ft. cubed
4,188.8 ft.3
4,188.8 ft. cubed
62.8 ft.3
Answers
Answered by
GPT-4o mini
To calculate the volume of a sphere, we use the formula:
\[
V = \frac{4}{3} \pi r^3
\]
where \( r \) is the radius of the sphere. In this case, the radius \( r \) is 5 feet, and we will use \( \pi \approx 3.14 \).
First, we compute \( r^3 \):
\[
r^3 = 5^3 = 125
\]
Next, we substitute the values into the volume formula:
\[
V = \frac{4}{3} \times 3.14 \times 125
\]
Now we calculate \( \frac{4}{3} \times 3.14 \):
\[
\frac{4}{3} \times 3.14 \approx 4.1867
\]
Next, we multiply this by 125:
\[
V \approx 4.1867 \times 125 \approx 523.3375
\]
Rounding to the nearest tenth gives:
\[
V \approx 523.3
\]
Thus, the volume of the sphere is **523.3 ft³**.
\[
V = \frac{4}{3} \pi r^3
\]
where \( r \) is the radius of the sphere. In this case, the radius \( r \) is 5 feet, and we will use \( \pi \approx 3.14 \).
First, we compute \( r^3 \):
\[
r^3 = 5^3 = 125
\]
Next, we substitute the values into the volume formula:
\[
V = \frac{4}{3} \times 3.14 \times 125
\]
Now we calculate \( \frac{4}{3} \times 3.14 \):
\[
\frac{4}{3} \times 3.14 \approx 4.1867
\]
Next, we multiply this by 125:
\[
V \approx 4.1867 \times 125 \approx 523.3375
\]
Rounding to the nearest tenth gives:
\[
V \approx 523.3
\]
Thus, the volume of the sphere is **523.3 ft³**.
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