Let's tackle each part of your question step-by-step.
Part A: Graph the function
For Part A, you can use the function \( g(x) = 3x + 2 \) and enter it into Desmos to graph it. Unfortunately, I cannot create or display graphs here, but you can easily plot it on the Desmos graphing calculator.
Part B: Find \( g(8) \)
To find \( g(8) \): \[ g(8) = 3(8) + 2 = 24 + 2 = 26 \] Thus, \( g(8) = 26 \).
Part C: Solve \( -1 = 3x + 2 \)
To solve for \( x \):
- Start with the equation: \[ -1 = 3x + 2 \]
- Subtract 2 from both sides: \[ -1 - 2 = 3x \] \[ -3 = 3x \]
- Divide by 3: \[ x = -1 \] Thus, \( x = -1 \).
Part D: Find the x-value for which \( g(x) = 8 \)
We need to solve the equation \( g(x) = 8 \):
- Set the equation: \[ 3x + 2 = 8 \]
- Subtract 2 from both sides: \[ 3x = 6 \]
- Divide by 3: \[ x = 2 \] Thus, \( x = 2 \).
Part E: Key feature shown by \( g(0) \)
To find \( g(0) \): \[ g(0) = 3(0) + 2 = 2 \] Thus, \( g(0) = 2 \), and in terms of key features:
- \( g(0) \) gives the y-intercept of the function, because it represents the value of the function when \( x = 0 \).
In summary:
- Part B: \( g(8) = 26 \)
- Part C: \( x = -1 \)
- Part D: \( x = 2 \)
- Part E: \( g(0) \) is the y-intercept.