Question

Tonya has a small picture with a length of 4 1/5
inches. She wants to enlarge the picture by a factor of 7 and frame it. Which of the following is true?
A.
The enlarged picture has a length of 28 1/5
inches.

B.
The enlarged picture has a length of 29 2/5
inches.

C.
The enlarged picture has a length of 16
inches.

D.
The enlarged picture has a length of 5 3/5
inches.

Answer 1

To find the enlarged length of the picture, we need to multiply the original length by the enlargement factor.

The original length is \( 4 \frac{1}{5} \) inches. We can convert this into an improper fraction:

\[
4 \frac{1}{5} = \frac{21}{5}
\]

Next, we multiply this by the enlargement factor of 7:

\[
\frac{21}{5} \times 7 = \frac{21 \times 7}{5} = \frac{147}{5}
\]

Now, we convert \( \frac{147}{5} \) back into a mixed number. We divide 147 by 5:

\[
147 \div 5 = 29 \text{ with a remainder of } 2
\]

This gives us:

\[
\frac{147}{5} = 29 \frac{2}{5}
\]

Thus, the enlarged picture has a length of \( 29 \frac{2}{5} \) inches.

The correct answer is:

**B. The enlarged picture has a length of 29 2/5 inches.**