To determine whether the graph represents the equation \(3x - y = 10\), we need to analyze the slope and y-intercept of the line.
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Rearranging the Equation:
Start with the equation \(3x - y = 10\).
Rearranging it to slope-intercept form (\(y = mx + b\)): \[ -y = -3x + 10 \quad \text{(add } y \text{ to both sides)}
y = 3x - 10 \] Here, the slope (\(m\)) is 3, and the y-intercept (\(b\)) is \(-10\), meaning the line crosses the y-axis at point (0, -10). -
Checking Points on the Graph:
The graph mentions points (0, -10) and (1, -7):- The point (0, -10) matches the y-intercept from our equation.
- To check the point (1, -7): Substitute \(x = 1\) in the equation \(y = 3x - 10\): \[ y = 3(1) - 10 = 3 - 10 = -7 \] Thus, the point (1, -7) is also on the line.
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Conclusion:
The slope from the rearranged equation is 3, and the y-intercept is indeed (0, -10). Both points (0, -10) and (1, -7) lie on the line described by the equation.
Therefore, the correct response is:
Yes, it is the correct graph because the slope is 3 and the y-intercept is (0, −10).