To find the initial value (the y-intercept) of the linear function, we can use the slope-intercept form of a linear equation, which is:
\[ y = mx + b \]
where:
- \( m \) is the slope (rate of change),
- \( b \) is the y-intercept,
- \( (x, y) \) is a point on the line.
Given:
- Slope \( m = -\frac{4}{7} \)
- Point \( (14, 3) \)
We can substitute the values into the equation to find \( b \):
-
Substitute \( m \), \( x \), and \( y \) into the equation:
\[ 3 = -\frac{4}{7}(14) + b \]
-
Calculate \( -\frac{4}{7}(14) \):
\[ -\frac{4 \times 14}{7} = -\frac{56}{7} = -8 \]
-
Now substitute back into the equation:
\[ 3 = -8 + b \]
-
Solve for \( b \):
\[ b = 3 + 8 = 11 \]
So the y-intercept (initial value) \( b = 11 \).
The correct response is:
b equals 11