Question
The circle-shaped part of the necklace above has a diameter of 5 mm.
The circumference of the circle-shaped part of each of the earrings is one-half the circumference of the necklace.
What is the circumference of the circle-shaped part of one of the earrings? (Use 3.14 for .)
A.
15.7 mm
B.
3.925 mm
C.
31.4 mm
D.
7.85 mm
The circumference of the circle-shaped part of each of the earrings is one-half the circumference of the necklace.
What is the circumference of the circle-shaped part of one of the earrings? (Use 3.14 for .)
A.
15.7 mm
B.
3.925 mm
C.
31.4 mm
D.
7.85 mm
Answers
GPT-4o mini
To find the circumference of the circle-shaped part of the necklace, we use the formula for the circumference of a circle:
\[
C = \pi d
\]
where \(d\) is the diameter.
Given that the diameter of the necklace is 5 mm, we can calculate the circumference as follows:
\[
C_{\text{necklace}} = 3.14 \times 5 = 15.7 \text{ mm}
\]
The problem states that the circumference of the circle-shaped part of each of the earrings is one-half the circumference of the necklace. Therefore, we need to calculate one-half of the circumference of the necklace:
\[
C_{\text{earring}} = \frac{1}{2} C_{\text{necklace}} = \frac{1}{2} \times 15.7 = 7.85 \text{ mm}
\]
Thus, the circumference of the circle-shaped part of one of the earrings is:
\[
\boxed{7.85 \text{ mm}}
\]
So the correct option is **D. 7.85 mm**.
\[
C = \pi d
\]
where \(d\) is the diameter.
Given that the diameter of the necklace is 5 mm, we can calculate the circumference as follows:
\[
C_{\text{necklace}} = 3.14 \times 5 = 15.7 \text{ mm}
\]
The problem states that the circumference of the circle-shaped part of each of the earrings is one-half the circumference of the necklace. Therefore, we need to calculate one-half of the circumference of the necklace:
\[
C_{\text{earring}} = \frac{1}{2} C_{\text{necklace}} = \frac{1}{2} \times 15.7 = 7.85 \text{ mm}
\]
Thus, the circumference of the circle-shaped part of one of the earrings is:
\[
\boxed{7.85 \text{ mm}}
\]
So the correct option is **D. 7.85 mm**.