what is the area of the sector of a circle with θ = 75 degrees and a radius of 4 feet?

1 answer

To find the area of a sector of a circle, you can use the formula:

\[ \text{Area} = \frac{\theta}{360} \times \pi r^2 \]

where:

  • \(\theta\) is the angle of the sector in degrees,
  • \(r\) is the radius of the circle.

In this case, \(\theta = 75\) degrees and \(r = 4\) feet. Plugging in these values:

\[ \text{Area} = \frac{75}{360} \times \pi \times (4^2) \]

Calculating \(4^2\):

\[ 4^2 = 16 \]

Now substitute this back into the equation:

\[ \text{Area} = \frac{75}{360} \times \pi \times 16 \]

Calculating \(\frac{75}{360}\):

\[ \frac{75}{360} = \frac{5}{24} \]

Now substitute that into the area formula:

\[ \text{Area} = \frac{5}{24} \times \pi \times 16 \]

Calculating \( \frac{5 \times 16}{24} \):

\[ \frac{5 \times 16}{24} = \frac{80}{24} = \frac{10}{3} \]

Thus, the area becomes:

\[ \text{Area} = \frac{10}{3} \pi \text{ square feet} \]

If you want a numerical approximation, using \(\pi \approx 3.14\):

\[ \text{Area} \approx \frac{10}{3} \times 3.14 \approx 10.47 \text{ square feet} \]

So, the area of the sector is:

\[ \frac{10}{3} \pi \text{ square feet} \quad \text{or approximately } 10.47 \text{ square feet.} \]