Question

The rectangle below has an area of 27y^5 square meters and a length of 9y^4 meters.
What is the width of the rectangle?

Answer 1

To find the width of the rectangle, we can use the formula for the area of a rectangle, which is:

\[
\text{Area} = \text{Length} \times \text{Width}
\]

We are given that the area is \(27y^5\) square meters and the length is \(9y^4\) meters. We need to find the width, which we can denote as \(w\).

Plugging in the values we have:

\[
27y^5 = 9y^4 \times w
\]

To isolate \(w\), we can divide both sides by \(9y^4\):

\[
w = \frac{27y^5}{9y^4}
\]

Now, let's perform the division:

1. Divide the coefficients: \( \frac{27}{9} = 3 \)
2. Subtract the exponents of \(y\): \(y^{5 - 4} = y^1 = y\)

Putting it all together, we have:

\[
w = 3y
\]

Thus, the width of the rectangle is

\[
\boxed{3y} \text{ meters}.
\]