Given 2x^2=32

Solve for x

(1 point)
x=± (__)

1 answer

To solve the equation \( 2x^2 = 32 \), you first divide both sides by 2:

\[ x^2 = \frac{32}{2} \] \[ x^2 = 16 \]

Next, take the square root of both sides:

\[ x = \pm \sqrt{16} \] \[ x = \pm 4 \]

Thus, the solution for \( x \) is:

\[ x = \pm 4 \]

So, filling in the blank, the answer is \( 4 \). Final answer:

\[ x = \pm (4) \]