To evaluate \( f(-3) \) for the function \( f(x) = 2x^2 + 3x - 5 \), we will substitute \( -3 \) into the function.
\[ f(-3) = 2(-3)^2 + 3(-3) - 5 \]
Calculating \( (-3)^2 \):
\[ (-3)^2 = 9 \]
Now substituting this value into the equation:
\[ f(-3) = 2(9) + 3(-3) - 5 \]
This simplifies to:
\[ f(-3) = 18 - 9 - 5 \]
Now combining the numbers:
\[ f(-3) = 18 - 9 = 9 \] \[ f(-3) = 9 - 5 = 4 \]
Thus,
\[ f(-3) = 4 \]
So the final answer is:
\[ f(-3) = \boxed{4} \]