Bowls A and B contain a number of white and red balls. Simon repeatedly selected a ball from both bowls and recorded the results in a table. Using Simon’s results, what is the experimental probability of picking a red ball from Bowl A? The answer needs to be in percent form.

(1 point)
Responses

78.95%
78.95%

25%
25%

75%
75%

37.5%
37.5%

1 answer

To calculate the experimental probability of picking a red ball from Bowl A, we need the number of red balls chosen from Bowl A and the total number of balls drawn from Bowl A.

The experimental probability formula is given by:

\[ \text{Probability} = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} \]

  1. Find the number of times a red ball was picked from Bowl A (let's call this \( R_A \)).
  2. Find the total number of picks from Bowl A (let's call this \( T_A \)).
  3. Calculate the probability: \( P(\text{Red from A}) = \frac{R_A}{T_A} \).
  4. Convert the probability into a percentage by multiplying by 100.

Since you didn't provide specific numbers from Simon's results, I can't compute the exact probability. However, if you have data:

  • If \( R_A \) equals 15 and \( T_A \) equals 19, for example:

\[ P(\text{Red from A}) = \frac{15}{19} \approx 0.7895 \]

To convert that into a percentage:

\[ 0.7895 \times 100 \approx 78.95% \]

You would then select 78.95% as the answer if those were the results. Please provide the actual counts from Simon's results if you need a precise answer!