Question
How can you find an approximate answer for the equation 10e0.1x=53
?(1 point)
Responses
Find the x-intercept of f(x)=10e0.1x
.
Find the x -intercept of f left parenthesis x right parenthesis equals 10 e superscript 0.1 x baseline .
Find the intersection of f(x)=10e0.1x
and g(x)=53
.
Find the intersection of f left parenthesis x right parenthesis equals 10 e superscript 0.1 x baseline and g left parenthesis x right parenthesis equals 53 .
Find the horizontal asymptote of f(x)=10e0.1x
and add it to 53.
Find the horizontal asymptote of f left parenthesis x right parenthesis equals 10 e superscript 0.1 x baseline and add it to 53.
Find the vertex of f(x)=10e0.1x
.
?(1 point)
Responses
Find the x-intercept of f(x)=10e0.1x
.
Find the x -intercept of f left parenthesis x right parenthesis equals 10 e superscript 0.1 x baseline .
Find the intersection of f(x)=10e0.1x
and g(x)=53
.
Find the intersection of f left parenthesis x right parenthesis equals 10 e superscript 0.1 x baseline and g left parenthesis x right parenthesis equals 53 .
Find the horizontal asymptote of f(x)=10e0.1x
and add it to 53.
Find the horizontal asymptote of f left parenthesis x right parenthesis equals 10 e superscript 0.1 x baseline and add it to 53.
Find the vertex of f(x)=10e0.1x
.
Answers
GPT-4o mini
To find an approximate answer for the equation \( 10e^{0.1x} = 53 \), you would typically look for the intersection of the function on the left side, \( f(x) = 10e^{0.1x} \), with a constant line representing the right side of the equation, \( g(x) = 53 \).
This means you're looking for:
**Find the intersection of \( f(x) = 10e^{0.1x} \) and \( g(x) = 53 \).**
This method will give you the values for \( x \) where the two functions are equal, hence providing an approximate solution for the equation.
This means you're looking for:
**Find the intersection of \( f(x) = 10e^{0.1x} \) and \( g(x) = 53 \).**
This method will give you the values for \( x \) where the two functions are equal, hence providing an approximate solution for the equation.