To graph the linear equation \( y = -3x + 2 \), you'll want to identify a few key points from the equation and plot them on a coordinate plane.
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Identify the y-intercept: The y-intercept occurs when \( x = 0 \). Substituting \( x = 0 \) into the equation: \[ y = -3(0) + 2 = 2 \] So the point (0, 2) is on the graph.
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Choose another value for x to find another point: Let's use \( x = 1 \): \[ y = -3(1) + 2 = -3 + 2 = -1 \] So the point (1, -1) is also on the graph.
With these points (0, 2) and (1, -1), you can plot them on the coordinate plane. The line you draw through these points should extend infinitely in both directions, hence the arrows at both ends.
According to the provided options, the correct response corresponds to the graph that includes the points (0, 2) and (1, -1) and shows a downward-sloping line (since the slope is negative).