Question
14a) Use the change of base formula to complete the fraction.
logv5 37 =_/_
a. logv5 10
b. logv10 5
c. logv10 37
d. logv37 10
Evaluate logv5 37
A. 2.244
B. 1.568
C. 0.446
D. 0.699
logv5 37 =_/_
a. logv5 10
b. logv10 5
c. logv10 37
d. logv37 10
Evaluate logv5 37
A. 2.244
B. 1.568
C. 0.446
D. 0.699
Answers
GPT-4o mini
The change of base formula for logarithms states that:
\[
\log_b a = \frac{\log_k a}{\log_k b}
\]
where \( k \) can be any positive number. In this case, we want to express \(\log_5 37\) using base 10 logarithms (common logarithm).
Thus, we can write:
\[
\log_5 37 = \frac{\log_{10} 37}{\log_{10} 5}
\]
So the correct answer for the fraction is:
\[
\log_5 37 = \frac{\log_{10} 37}{\log_{10} 5}
\]
Now we evaluate \(\log_5 37\). To find the numerical value of \(\log_5 37\), we can use a calculator to find \(\log_{10} 37\) and \(\log_{10} 5\):
\[
\log_{10} 37 \approx 1.568
\]
\[
\log_{10} 5 \approx 0.699
\]
Now we can calculate \(\log_5 37\):
\[
\log_5 37 \approx \frac{1.568}{0.699} \approx 2.244
\]
Thus, the evaluation of \(\log_5 37\) gives us approximately \(2.244\).
So the final answers are:
1. The fraction: \(\frac{\log_{10} 37}{\log_{10} 5}\)
2. The evaluated value of \(\log_5 37\): **A. 2.244**.
\[
\log_b a = \frac{\log_k a}{\log_k b}
\]
where \( k \) can be any positive number. In this case, we want to express \(\log_5 37\) using base 10 logarithms (common logarithm).
Thus, we can write:
\[
\log_5 37 = \frac{\log_{10} 37}{\log_{10} 5}
\]
So the correct answer for the fraction is:
\[
\log_5 37 = \frac{\log_{10} 37}{\log_{10} 5}
\]
Now we evaluate \(\log_5 37\). To find the numerical value of \(\log_5 37\), we can use a calculator to find \(\log_{10} 37\) and \(\log_{10} 5\):
\[
\log_{10} 37 \approx 1.568
\]
\[
\log_{10} 5 \approx 0.699
\]
Now we can calculate \(\log_5 37\):
\[
\log_5 37 \approx \frac{1.568}{0.699} \approx 2.244
\]
Thus, the evaluation of \(\log_5 37\) gives us approximately \(2.244\).
So the final answers are:
1. The fraction: \(\frac{\log_{10} 37}{\log_{10} 5}\)
2. The evaluated value of \(\log_5 37\): **A. 2.244**.