Question

Bud and his friends stopped at a local fast food restaurant after the football game Friday night. Bud ate a one-fourth pound cheeseburger and a large order of fries. The cheeseburger contained 30 grams of total fat. If the recommended daily allowance of total fat for a 2,000 calorie diet is 64 grams, what percent of the daily allowance did Bud have when he ate the cheeseburger?

Answer 1

To find the percent of the daily allowance of total fat that Bud consumed from the cheeseburger, we can use the following formula:

\[
\text{Percent of daily allowance} = \left( \frac{\text{Fat consumed}}{\text{Recommended daily allowance}} \right) \times 100
\]

From the problem:
- Fat consumed (from the cheeseburger) = 30 grams
- Recommended daily allowance = 64 grams

Now, we can plug in the values into the formula:

\[
\text{Percent of daily allowance} = \left( \frac{30 \, \text{grams}}{64 \, \text{grams}} \right) \times 100
\]

Calculating the fraction:

\[
\frac{30}{64} = 0.46875
\]

Now, multiplying by 100 to convert it to a percentage:

\[
0.46875 \times 100 = 46.875\%
\]

Therefore, rounding to two decimal places, Bud consumed approximately:

\[
\boxed{46.88\%}
\]

of the daily allowance of total fat when he ate the cheeseburger.