To find the number of different arrangements of 3 plants that Asher can choose from 5 plants (taking into account the order of the arrangements), we can use the formula for permutations:
\[ P(n, r) = \frac{n!}{(n - r)!} \]
Where:
- \( n \) is the total number of items to choose from (in this case, 5 plants),
- \( r \) is the number of items to arrange (in this case, 3 plants).
Substituting the values into the formula:
\[ P(5, 3) = \frac{5!}{(5 - 3)!} = \frac{5!}{2!} \]
Calculating the factorials:
\[ 5! = 5 \times 4 \times 3 \times 2 \times 1 = 120 \] \[ 2! = 2 \times 1 = 2 \]
Now substituting these values back into the permutation formula:
\[ P(5, 3) = \frac{120}{2} = 60 \]
Therefore, the number of different arrangements of 3 plants out of the 5 is 60.
So the correct response is:
60