Question
The probability that a student is a sophomore or a male is 0.55. The probability that a student is a sophomore is 0.32. The probability that a student is a male is 0.41. What is the probability that a student is a sophomore and male?
A.
0.13
B.
0.18
C.
0.45
D.
0.73
A.
0.13
B.
0.18
C.
0.45
D.
0.73
Answers
GPT-4o mini
To find the probability that a student is both a sophomore and male, we can use the formula for the probability of the union of two events:
\[
P(A \cup B) = P(A) + P(B) - P(A \cap B)
\]
Where:
- \( P(A \cup B) \) is the probability that a student is a sophomore or male.
- \( P(A) \) is the probability that a student is a sophomore.
- \( P(B) \) is the probability that a student is male.
- \( P(A \cap B) \) is the probability that a student is both a sophomore and male.
From the problem:
- \( P(A \cup B) = 0.55 \)
- \( P(A) = 0.32 \)
- \( P(B) = 0.41 \)
Now we can rearrange the formula to solve for \( P(A \cap B) \):
\[
P(A \cap B) = P(A) + P(B) - P(A \cup B)
\]
Substituting in the values:
\[
P(A \cap B) = 0.32 + 0.41 - 0.55
\]
Calculating this gives:
\[
P(A \cap B) = 0.73 - 0.55 = 0.18
\]
Thus, the probability that a student is a sophomore and male is \( 0.18 \).
The answer is:
**B. 0.18**
\[
P(A \cup B) = P(A) + P(B) - P(A \cap B)
\]
Where:
- \( P(A \cup B) \) is the probability that a student is a sophomore or male.
- \( P(A) \) is the probability that a student is a sophomore.
- \( P(B) \) is the probability that a student is male.
- \( P(A \cap B) \) is the probability that a student is both a sophomore and male.
From the problem:
- \( P(A \cup B) = 0.55 \)
- \( P(A) = 0.32 \)
- \( P(B) = 0.41 \)
Now we can rearrange the formula to solve for \( P(A \cap B) \):
\[
P(A \cap B) = P(A) + P(B) - P(A \cup B)
\]
Substituting in the values:
\[
P(A \cap B) = 0.32 + 0.41 - 0.55
\]
Calculating this gives:
\[
P(A \cap B) = 0.73 - 0.55 = 0.18
\]
Thus, the probability that a student is a sophomore and male is \( 0.18 \).
The answer is:
**B. 0.18**