Question

A bag contained 12 blue raspberry and 8 strawberry gumballs. Chancey randomly selected one strawberry gumball from the bag and ate it. Chancey's buddy Josiah randomly chose the next gumball from the same bag. What is the probability that Josiah selected a strawberry gumball after Chancey selected his?

Round your answer to the nearest hundredth.

Group of answer choices

.37

.35

.40

.15

Answer 1

Initially, the bag contains:

- 12 blue raspberry gumballs
- 8 strawberry gumballs

This gives a total of \( 12 + 8 = 20 \) gumballs.

When Chancey selects and eats one strawberry gumball, the remaining gumballs in the bag are:

- 12 blue raspberry gumballs
- \( 8 - 1 = 7 \) strawberry gumballs

This results in a new total of:

- \( 12 + 7 = 19 \) gumballs left in the bag.

Now, to find the probability that Josiah selects a strawberry gumball, we need to calculate the number of strawberry gumballs divided by the total number of gumballs remaining:

\[
\text{Probability (Josiah selects a strawberry gumball)} = \frac{\text{Number of strawberry gumballs left}}{\text{Total number of gumballs left}} = \frac{7}{19}
\]

Now we will calculate \( \frac{7}{19} \):

\[
\frac{7}{19} \approx 0.3684
\]

Rounding this to the nearest hundredth gives:

\[
0.37
\]

Therefore, the probability that Josiah selected a strawberry gumball after Chancey selected his is **0.37**.