To solve the equation \( x^2 - 20x = -90 \) by completing the square, we follow these steps:
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Move the constant to the other side of the equation: \[ x^2 - 20x + 90 = 0 \]
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Complete the square for the expression \( x^2 - 20x \): To complete the square, we take half of the coefficient of \( x \) (which is \(-20\)), square it, and add it to both sides. Half of \(-20\) is \(-10\), and squaring it gives \(100\).
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Add and subtract \(100\) on the left side: \[ x^2 - 20x + 100 = 10 \] Now, we can rewrite the left side as a perfect square: \[ (x - 10)^2 = 10 \]
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Take the square root of both sides: \[ x - 10 = \pm \sqrt{10} \]
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Solve for \( x \): \[ x = 10 \pm \sqrt{10} \]
Thus, the solutions are: \[ x = 10 + \sqrt{10} \quad \text{and} \quad x = 10 - \sqrt{10} \]
In simplest form, the solutions to the equation \( x^2 - 20x = -90 \) are:
\[ \boxed{10 + \sqrt{10}} \quad \text{and} \quad \boxed{10 - \sqrt{10}} \]