Question
20kg mass is pushed with a force of 30N so that it moves. Calculate the acceleration of the mass.
Responses
1.5
1.5the fraction with numerator m and denominator s squared
50
50the fraction with numerator m and denominator s squared
0.6
0.6the fraction with numerator m and denominator s squared
10
Responses
1.5
1.5the fraction with numerator m and denominator s squared
50
50the fraction with numerator m and denominator s squared
0.6
0.6the fraction with numerator m and denominator s squared
10
Answers
GPT-4o mini
To calculate the acceleration of the mass, we can use Newton's second law of motion, which states:
\[ F = ma \]
Where:
- \( F \) is the net force (in newtons)
- \( m \) is the mass (in kilograms)
- \( a \) is the acceleration (in meters per second squared)
Rearranging the formula to solve for acceleration (\( a \)) gives us:
\[ a = \frac{F}{m} \]
Given:
- \( F = 30 \, \text{N} \)
- \( m = 20 \, \text{kg} \)
Substituting in the values:
\[ a = \frac{30 \, \text{N}}{20 \, \text{kg}} \]
\[ a = 1.5 \, \text{m/s}^2 \]
So the acceleration of the mass is \( 1.5 \, \text{m/s}^2 \).
Thus, the correct response is:
**1.5 the fraction with numerator m and denominator s squared**
\[ F = ma \]
Where:
- \( F \) is the net force (in newtons)
- \( m \) is the mass (in kilograms)
- \( a \) is the acceleration (in meters per second squared)
Rearranging the formula to solve for acceleration (\( a \)) gives us:
\[ a = \frac{F}{m} \]
Given:
- \( F = 30 \, \text{N} \)
- \( m = 20 \, \text{kg} \)
Substituting in the values:
\[ a = \frac{30 \, \text{N}}{20 \, \text{kg}} \]
\[ a = 1.5 \, \text{m/s}^2 \]
So the acceleration of the mass is \( 1.5 \, \text{m/s}^2 \).
Thus, the correct response is:
**1.5 the fraction with numerator m and denominator s squared**