To find the volume of a right rectangular prism, you multiply its length, width, and height. Given that the dimensions of the prism are:
- Length = 12 m
- Width = 14 m
- Height = 54 m
The volume \( V \) can be calculated using the formula:
\[ V = \text{Length} \times \text{Width} \times \text{Height} \]
Substituting the values:
\[ V = 12 , \text{m} \times 14 , \text{m} \times 54 , \text{m} \]
Now, calculating step-by-step:
- \( 12 \times 14 = 168 \)
- \( 168 \times 54 = 9072 \)
Therefore, the volume of the prism is:
\[ V = 9072 , \text{cubic meters} \]
If you are also considering packing the prism with unit cubes that each have an edge length of 14 m, these cubes would each have a volume of:
\[ \text{Volume of one cube} = 14 , \text{m} \times 14 , \text{m} \times 14 , \text{m} = 2744 , \text{cubic meters} \]
If you pack 10 such cubes, the total volume packed is:
\[ \text{Total volume} = 10 \times 2744 , \text{cubic meters} = 27440 , \text{cubic meters} \]
This seems to align with the problem context rather than the direct volume of the prism.
In conclusion, the volume of the first prism is:
\[ \boxed{9072} , \text{cubic meters} \]